Write the dictiоnаry returned when the fоllоwing function is pаssed eаch of the following pairs of dictionaries. def mystery(dict1, dict2): result = {} for s in dict1: if dict1[s] in dict2: result[s] = dict2[dict1[s]] return result Though dictionaries store their contents in unpredictable order, for this problem, write the pairs sorted by alphabetical ordering of the keys. Write your answer in this format: {'key':'value','key':'value'} - WITH NO SPACES dict1 = {"bar": 1, "baz": 2, "foo": 3, "mumble": 4}, dict2 = {1: "earth", 2: "wind", 3: "air", 4: "fire"} [a1] dict1 = {"a": 42, "b": 9, "c": 7, "d": 15, "e": 11, "f": 24, "g": 7}, dict2 = {1: "four", 3: "score", 5: "and", 7: "seven", 9: "years", 11: "ago"} [a2]