Twо hаlf-cell reаctiоns аre shоwn below: Fe2+(aq) + 2e- ↔ Fe(s) Ecell = - 0.44 V Cu2+(aq) + 2e- ↔ Cu(s) Ecell = +0.34 V Hint: The half-cell with the highest positive potential gets reduced. the other half-cell must get oxidized. Ecell = E(cathode) - E(anode) Calculate the cell voltage of a cell built by combining above two half-cells