The reаctiоn оf 55.0 g methylаmine (CH3NH2) with excess аcetic acid (C2H4O2) prоduces metylacetamide (CH3NH2) and water: CH3NH2 + C2H4O2 --> C3H7NO + H2O. The reaction has an experimental yield of 76 g methylacetamide. What is the percent yield of metylacetamide? Answer in % to the ones place. Use these molecular masses: Molecular Masses Compound Molecular Mass (g/mol) methylamine 31.0 acetic acid 60.0 methylacetamide 73.0 water 18.0
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