Write the full electron configuration for S: (Do not consider exceptions. Make sure to follow the order following the Aufbau principle, use the following format without superscripts: 1s2 2s2 2p6…)
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When a 1.397 g sample of thymol, C10H14O(s) (a preservative)…
When a 1.397 g sample of thymol, C10H14O(s) (a preservative), is burned in a bomb calorimeter. The temperature increase from 20.00 °C to 31.23 °C, and the heat capacity of the bomb calorimeter is 4.68 kJ/°C. What is the heat of combustion of thymol, expressed in kilojoules per mole of C10H14O?
Write the condensed (short form) electron configuration for…
Write the condensed (short form) electron configuration for Fr:( Make sure to follow the order following the Aufbau principle. Do not consider exceptions. Do not use superscripts, do not write the brackets on the noble gas. Use the following format Ne – 3s2 ….)
Given the data: N2H4(l) + O2 (g) → N2(g) + 2 H2O (l)…
Given the data: N2H4(l) + O2 (g) → N2(g) + 2 H2O (l) ΔH° = – 622.2 kJ 2 H2(g) + O2 (g) → 2H2O (l) ΔH° = -571.6 kJ H2(g) + O2 (g) → H2O2(l) ΔH° = – 187.8 kJ using Hess’s Law the ∆H for the reaction below is [a] kJ:N2H4 (l) + 2 H2O2 (l) → N2(g) + 4 H2O (l)Must show your work (scratch paper) to receive credit.
Given the following equations and ∆H° values: …
Given the following equations and ∆H° values: OF2(g) + H2O(l) → O2(g) + 2 HF(g) ∆H° = -276.6 kJ SF4(g) + 2 H2O(l) → 4 HF(g) + SO2(g) ∆H° = -827.5 kJ S(s) + O2(g) → SO2(g) ∆H° = -296.9 kJ determine the heat of reaction (kJ) at 298 K for the reaction: 2 OF2(g) + 2 S(s) →SO2(g) + SF4(g) Must show your work (scratch paper) to receive credit.
A coffee-cup calorimeter contains 100.0 mL of 1.000 M HCl (e…
A coffee-cup calorimeter contains 100.0 mL of 1.000 M HCl (excess) at 20.3 °C. When 1.82 g Zn(s) is added, the temperature rises to 30.5 °C. What is the heat of reaction per mol Zn? Assume that the heat of solution is that of water, and the density of the HCl is 1.000 g/mL. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)
When you look out the window at the blue sky you see light o…
When you look out the window at the blue sky you see light of a wavelenth of 473 nm. A photon of that light has a frequency of [a]Hz and an energy of [b] J. Must show your work (scratch paper) to receive credit.
A coffee-cup calorimeter contains 100.0 mL of 1.000 M HCl (e…
A coffee-cup calorimeter contains 100.0 mL of 1.000 M HCl (excess) at 20.3 °C. When 1.82 g Zn(s) is added, the temperature rises to 30.5 °C. What is the heat of reaction per mol Zn? Assume that the heat of solution is that of water, and the density of the HCl is 1.000 g/mL. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)
Use Hess’s Law and the following data CH4(g) + 2 O2(g)…
Use Hess’s Law and the following data CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g) ΔH = −802 kJ CH4(g) + CO2(g) → 2 CO(g) + 2 H2(g) ΔH = + 247 kJ CH4(g) + H2O(g) → CO(g) + 3 H2(g) ΔH = + 206 kJ to determine the ∆H°rxn for the following reaction, an important source of hydrogen gas: 2 CH4(g) + O2(g) → 2 CO(g) + 4 H2(g) Must show your work (scratch paper) to receive credit.
Given the data: N2H4(l) + O2 (g) → N2(g) + 2 H2O (l)…
Given the data: N2H4(l) + O2 (g) → N2(g) + 2 H2O (l) ΔH° = – 622.2 kJ 2 H2(g) + O2 (g) → 2H2O (l) ΔH° = -571.6 kJ H2(g) + O2 (g) → H2O2(l) ΔH° = – 187.8 kJ using Hess’s Law the ∆H for the reaction below is [a] kJ:N2H4 (l) + 2 H2O2 (l) → N2(g) + 4 H2O (l)Must show your work (scratch paper) to receive credit.