Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of K2CO3 and HBr are mixed.
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A sample of calcium fluoride was decomposed into its constit…
A sample of calcium fluoride was decomposed into its constituent elements. If the sample produced 294 mg of calcium, how many g of fluorine was formed?
How many moles of oxygen are formed when 54.6 g of KNO3 deco…
How many moles of oxygen are formed when 54.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. 4 KNO3(s) → 2 K2O(s) + 2 N2(g) + 5 O2(g)
How many moles of nitrogen are formed when 48.6 g of KNO3 de…
How many moles of nitrogen are formed when 48.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. 4 KNO3(s) → 2 K2O(s) + 2 N2(g) + 5 O2(g)
How many moles of nitrogen are formed when 38.6 g of KNO3 de…
How many moles of nitrogen are formed when 38.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. 4 KNO3(s) → 2 K2O(s) + 2 N2(g) + 5 O2(g)
Determine the molarity of a solution formed by dissolving 89…
Determine the molarity of a solution formed by dissolving 89.7 g LiBr in enough water to yield 750.0 mL of solution.
Give the net ionic equation for the reaction (if any) that o…
Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of MgSO3 and HI are mixed.
What volume of 0.305 M AgNO3 is required to react exactly wi…
What volume of 0.305 M AgNO3 is required to react exactly with 155.0 mL of 0.274 M Na2SO4 solution? Hint: You will want to write a balanced reaction. AgNO3 = 169.874 g/mol; Na2SO4 = 142.036 g/mol
How many moles of nitrogen are formed when 58.6 g of KNO3 de…
How many moles of nitrogen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. 4 KNO3(s) → 2 K2O(s) + 2 N2(g) + 5 O2(g)
How many grams of Li3N can be formed from 0.95 moles of Li? …
How many grams of Li3N can be formed from 0.95 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(g) → 2 Li3N(s)