A coffee-cup calorimeter contains 100.0 mL of 1.000 M HCl (e…

A coffee-cup calorimeter contains 100.0 mL of 1.000 M HCl (excess) at 20.3 °C. When 1.82 g Zn(s) is added, the temperature rises to 30.5 °C. What is the heat of reaction per mol Zn? Assume that the heat of solution is that of water, and the density of the HCl is 1.000 g/mL.   Zn(s)  + 2 HCl(aq)  → ZnCl2(aq)  + H2(g)   

A coffee-cup calorimeter contains 100.0 mL of 1.000 M HCl (e…

A coffee-cup calorimeter contains 100.0 mL of 1.000 M HCl (excess) at 20.3 °C. When 1.82 g Zn(s) is added, the temperature rises to 30.5 °C. What is the heat of reaction per mol Zn? Assume that the heat of solution is that of water, and the density of the HCl is 1.000 g/mL.   Zn(s)  + 2 HCl(aq)  → ZnCl2(aq)  + H2(g)   

Use Hess’s Law and the following data   CH4(g) + 2 O2(g)…

Use Hess’s Law and the following data   CH4(g) + 2 O2(g) → CO2(g)   +  2 H2O(g) ΔH = −802 kJ CH4(g) + CO2(g) → 2 CO(g)   +  2 H2(g) ΔH = + 247 kJ CH4(g) + H2O(g) → CO(g)   +  3 H2(g) ΔH = + 206 kJ   to determine the ∆H°rxn for the following reaction, an important source of hydrogen gas:   2 CH4(g) + O2(g) →  2 CO(g)   +  4 H2(g)   Must show your work (scratch paper) to receive credit.

Given the data:  N2H4(l) + O2 (g) → N2(g) + 2 H2O (l)…

Given the data:  N2H4(l) + O2 (g) → N2(g) + 2 H2O (l) ΔH° = – 622.2 kJ 2 H2(g) + O2 (g) → 2H2O (l) ΔH° = -571.6 kJ H2(g) + O2 (g) → H2O2(l) ΔH° = – 187.8 kJ   using Hess’s Law the ∆H for the reaction below is [a] kJ:N2H4 (l) + 2 H2O2 (l) → N2(g) + 4 H2O (l)Must show your work (scratch paper) to receive credit.

Given the following equations and ∆H° values:               …

Given the following equations and ∆H° values:                                                               OF2(g) + H2O(l) → O2(g) + 2 HF(g) ∆H° = -276.6 kJ SF4(g) + 2 H2O(l) → 4 HF(g) + SO2(g) ∆H° = -827.5 kJ S(s) + O2(g) → SO2(g) ∆H° = -296.9 kJ  determine the heat of reaction (kJ) at 298 K for the reaction:  2 OF2(g) + 2 S(s) →SO2(g) + SF4(g) Must show your work (scratch paper) to receive credit.

Use the standard enthalpies of formation provided to calcula…

Use the standard enthalpies of formation provided to calculate the change in enthalpy for the reaction below: 5 CO(g)  +  11 H2(g) → C5H12(l)   + 5 H2O(l)      ΔH°f (kJ/mol) CO(g)  – 110.5 H2O(l)  – 285.8 C5H12(l)    – 146.8 Must show your work (scratch paper) to receive credit.