Author: Anonymous

Solve the problem.A lake is stocked with 670 fish of a new variety. The size of the lake, the availability of food, and the number of other fish restrict growth in the lake to a limiting value of 4187. The population of fish in the lake after time t, in months, is given by the function, . Find the population after 10 month(s).

Solve the problem.A lake is stocked with 381 fish of a new variety. The size of the lake, the availability of food, and the number of other fish restrict growth in the lake to a limiting value of 2381. The population of fish in the lake after time t, in months, is given by the function, .  After how many months will the population be 1297?

Write the expression in expanded form.   

Solve the equation for x by first rewriting both sides as powers of the same base. 8x-1 = 642x

Solve the logarithmic equation. log (x + 10) – log (x + 4) = log x

Convert to an exponential equation.log464 = t

Solve the problem.How long will it take for the population of a certain country to double if its annual growth rate is 4.9%? Round to the nearest year.

Solve the logarithmic equation. log ( 4+ x) – log (x  – 3) = log  2

Solve the problem.The number of bacteria growing in an incubation culture increases with time according to n(t) = 9000(5)t where t is time in days. Find the number of bacteria when t = 0 and t = 4.

Determine the graph of the function.f(x) =  2.548x