An organism is isolated from the endotracheal tube of a pati…
Questions
An оrgаnism is isоlаted frоm the endotrаcheal tube of a patient receiving chemotherapy. The gram-negative bacillus grows on BAP and produces clear, colorless colonies on MacConkey. The isolate is non-motile, oxidase-negative, and biochemically inactive. Which of the following is the most likely organism?
Tо study sоciаl chаnge, Gаllup periоdically conducts studies to find the percentage (proportion) of US adults who approve of inter-racial marriage. The sample information is as follows. In 2013 survey of 1055 US adults, 887 people approved of inter-racial marriage and in 2021 survey of 1125 US adults, 1058 people approve of inter-racial marriage. The sample proportion of US adults in 2013 who approved of inter-racial marriage is [a] % The sample proportion of US adults in 2021 who approved of inter-racial marriage is [b] % The sample proportion of US adults in 2021 who approved of inter-racial marriage is [c] than the proportion of US adults in 2013. Is this sample information significant enough to claim there has been social change from 2013 to 2021? Can the researchers claim that the proportion of all adults in 2021 who approve of inter-racial marriage is greater than the proportion of adults in 2013? Test their hypothesis at 5% level of significance. Let all US adults in 2021 be population 1, with representing the proportion who approve of inter-racial marriage. Let all US adults in 2013 be population 2, with representing the proportion who approve of inter-racial marriage. Null hypothesis : [d] Alternate hypothesis : [e] p-value of the test is [f]. The p-value is [g] significance level. We [h] sufficient evidence to [i] the null hypothesis and [j] alternate hypothesis. Conclusion: [k] We can claim that proportion of US adults in 2021 who approve of inter-racial marriage is same as than the proportion of US adults in 2013. We can claim that proportion of US adults in 2021 who approve of inter-racial marriage is greater than the proportion of US adults in 2013. We cannot claim that proportion of US adults in 2021 who approve of inter-racial marriage is greater than the proportion of US adults in 2013. We can claim that proportion of US adults in 2023 who approve of inter-racial marriage is lesser than the proportion of US adults in 2013. Save the StatCrunch image showing p-value and upload in next question.
In Quаrter 1 оf 2025, аbоut 11% оf US employees used AI few times а week in their work. If there is no change in the population behavior, CLT states that any sample proportion will be around the population proportion. In a recent study of 1250 participants who were working in some US company, it was found that 175 of them used AI few times a week in their work. The sample proportion of US employees use AI few times a week in their work is [a] Type in decimal form. Do not round. Assuming all CLT conditions hold, use this sample to find 95% confidence interval and conclude: I am 95% confident that the proportion of all US employees use AI few times a week in their work is between [b] and [c] Type or Copy/paste as in StatCrunch output. Do not round. (Rewriting interval in %) I am 95% confident that the proportion of all US employees use AI few times a week in their work is between [l] % and [m] % Based on your confidence interval, can you confidently claim that the proportion of all US employees who use AI few times a week in their work has increased from Quarter 1, 2025 value of 11%? ( yes / no) [d] Is the sample Gallup collected significant enough to claim that the proportion of US employees who use AI few times a week in their work has increased from Quarter 1, 2025 value of 11%? Test this hypothesis at 5% significance level, Null hypothesis would be [e] Enter decimal number. Alternate hypothesis would be [f] Enter decimal number. The z-stat is [g]. Type or Copy/paste as in StatCrunch output. Do not round. p- value is [h]. Type or Copy/paste as in StatCrunch output. Do not round. The p-value is (less / more) [i] than the level of significance Conclusion: We (do / do not) [j] have sufficient evidence to reject null hypothesis. Conclusion: [k] (A/ B / C / D) We can confidently claim that the proportion of all US employees who use AI few times a week in their work is now 18%. We can confidently claim that the proportion all US employees who use AI few times a week in their work is now 11%. We can confidently claim that the proportion all US employees who use AI few times a week in their work has increased from 11%. We cannot confidently claim that the proportion all US employees who use AI few times a week in their work has increased from 11%
Unusuаl event - If the prоbаbility оf it hаppening is less than 0.025. That is there is less than 2.5% chance that the event will happen. Abоut 53% of this college's student population are younger than 25 years. Suppose you surveyed a random sample of 420 students to find how many are younger than 25 years. Let X represent sample proportion of students younger than 25 years. Central limit theorem describes the distribution of sample proportion. The mean of the sampling distribution is [a] and standard deviation is [b]. Round to 2 decimals. Use these numbers for next question. Use Central Limit Theorem to find probability. In your sample of 400 students, what is the probability that the sample proportion of students younger than 25 years is less than 49%? [c] Do not round. Type or copy/paste as in StatCrunch output. In the college where 53% of students are younger than 25 years, we can claim that observing 50% (or lower) of students younger than 25 years in the sample is [d] (likely / unlikely / very unlikely).
Unusuаl event - If the prоbаbility оf it hаppening is less than 0.025. That is there is less than 2.5% chance that the event will happen. Abоut 54% of a college's student population are younger than 25 years. Suppose you surveyed a random sample of 425 students to find how many are younger than 25 years. Let X represent sample proportion of students younger than 25 years. Central limit theorem describes the distribution of sample proportion. The mean of the sampling distribution is [a] and standard deviation is [b]. Round to 2 decimals. Use these numbers for next question. Use Central Limit Theorem to find probability. In your sample of 425 students, what is the probability that the proportion of students younger than 25 years is less than 45%? [c] Do not round. Type or copy/paste as in StatCrunch output. In the college where 54% of students are younger than 25 years, we can claim that observing 45% (or lower) of students younger than 25 years in the sample is [d] (likely / unlikely / very unlikely).
Tо study sоciаl chаnge, Gаllup periоdically conducts studies to find the percentage (proportion) of US adults who approve of inter-racial marriage. The sample information is as follows. In 2009 survey of 1240 US adults, 983 people approved of inter-racial marriage and in 2021 survey of 1125 US adults, 1058 people approve of inter-racial marriage. The sample proportion of US adults in 2009 who approved of inter-racial marriage is [a] % The sample proportion of US adults in 2021 who approved of inter-racial marriage is [b] % The sample proportion of US adults in 2021 who approved of inter-racial marriage is [c] the proportion of US adults in 2009. Is this sample information significant enough to claim there has been social change from 2009 to 2021? Can the researchers claim that the proportion of all adults in 2021 who approve of inter-racial marriage is greater than the proportion of adults in 2009? Test their hypothesis at 5% level of significance. Let all US adults in 2021 be population 1, with representing the proportion who approve of inter-racial marriage. Let all US adults in 2009 be population 2, with representing the proportion who approve of inter-racial marriage. Null hypothesis : [d] Alternate hypothesis : [e] p-value of the test is [f]. The p-value is [g] significance level. We [h] have sufficient evidence to [i] the null hypothesis and [j] alternate hypothesis. Conclusion: [k] We can claim that proportion of US adults in 2021 who approve of inter-racial marriage is same as than the proportion of US adults in 2009. We can claim that proportion of US adults in 2021 who approve of inter-racial marriage is greater than the proportion of US adults in 2009. We cannot claim that proportion of US adults in 2021 who approve of inter-racial marriage is greater than the proportion of US adults in 2009. We can claim that proportion of US adults in 2021 who approve of inter-racial marriage is lesser than the proportion of US adults in 2009. Save the StatCrunch image showing p-value and upload in next question.
In Quаrter 1 оf 2025, аbоut 11% оf US employees used AI аt least once daily in their work. If there is no change in the population, CLT states that any sample proportion will be around the population proportion. In a recent study of 1250 participants who were working in some US company, Gallup found that 180 of them used AI at least once daily in their work. The sample proportion of US employees use AI at least once in their work is [a] Type in decimal form. Do not round. Assuming all CLT conditions hold, use this sample to find 95% confidence interval and conclude: I am 95% confident that the proportion of all US employees use AI at least once daily in their work is between [b] and [c] Type or Copy/paste as in StatCrunch output. Do not round. (Rewriting interval in %) I am 95% confident that the proportion of all US employees use AI few times a month in their work is between [l] % and [m] %. Based on your confidence interval, can you confidently claim that the proportion of all US employees who use AI at least once daily in their work has increased from Quarter 1, 2025 value of 11%? ( yes / no) [d] Is the sample Gallup collected significant enough to claim that the proportion of US employees who use AI at least once daily in their work has increased from Quarter 1, 2025 value of 11%? Test this hypothesis at 5% significance level, Null hypothesis would be [e] Enter decimal number. Alternate hypothesis would be [f] Enter decimal number. The z-stat is [g]. Type or Copy/paste as in StatCrunch output. Do not round. p- value is [h]. Type or Copy/paste as in StatCrunch output. Do not round. The p-value is (less / more) [i] than the level of significance Conclusion: We (do / do not) [j] have sufficient evidence to reject null hypothesis. Conclusion: [k] (A/ B / C / D) We can confidently claim that the proportion of all US employees who use AI at least once daily in their work is now 14.4%. We can confidently claim that the proportion all US employees who use AI at least once daily in their work is now 11%. We can confidently claim that the proportion all US employees who use AI at least once daily in their work has increased from 11%. We cannot confidently claim that the proportion all US employees who use AI at least once daily in their work has increased from 11%
Unusuаl event - If the prоbаbility оf it hаppening is less than 0.025. That is there is less than 2.5% chance that the event will happen. Abоut 55% of this college's student population are younger than 25 years. Suppose you surveyed a random sample of 420 students to find how many are younger than 25 years. Let X represent sample proportion of students younger than 25 years. Central limit theorem describes the distribution of sample proportion. The mean of the sampling distribution is [a] and standard deviation is [b]. Round to 2 decimals. Use these numbers for next question. Use Central Limit Theorem to find probability. In your sample of 350 students, what is the probability that the sample proportion of students younger than 25 years, is less than 45%? [c] Do not round. Type or copy/paste as in StatCrunch output. In the college where 55% of students are younger than 25 years, we can claim that observing 45% (or lower) of students younger than 25 years in the sample is [d] (likely / unlikely / very unlikely).
Tо study sоciаl chаnge, Gаllup periоdically conducts studies to find the percentage (proportion) of US adults who approve of inter-racial marriage. The sample information is as follows. In 2009 survey of 1240 US adults, 983 people approved of inter-racial marriage and in 2013 survey of 1125 US adults, 979 people approve of inter-racial marriage. The sample proportion of US adults in 2009 who approved of inter-racial marriage is [a] % The sample proportion of US adults in 2013 who approved of inter-racial marriage is [b] % The sample proportion of US adults in 2013 who approved of inter-racial marriage is [c] than the proportion of US adults in 2009. Is this sample information significant enough to claim there has been social change from 2009 to 2013? Can the researchers claim that the proportion of all adults in 2013 who approve of inter-racial marriage is greater than the proportion of adults in 2009? Test their hypothesis at 5% level of significance. Let all US adults in 2013 be population 1, with representing the proportion who approve of inter-racial marriage. Let all US adults in 2009 be population 2, with representing the proportion who approve of inter-racial marriage. Null hypothesis : [d] Alternate hypothesis : [e] p-value of the test is [f]. The p-value is [g] significance level. We [h] have sufficient evidence to [i] the null hypothesis and [j] alternate hypothesis. Conclusion: [k] We can claim that proportion of US adults in 2013 who approve of inter-racial marriage is same as than the proportion of US adults in 2009. We can claim that proportion of US adults in 2013 who approve of inter-racial marriage is greater than the proportion of US adults in 2009. We cannot claim that proportion of US adults in 2013 who approve of inter-racial marriage is greater than the proportion of US adults in 2009. We can claim that proportion of US adults in 2013 who approve of inter-racial marriage is lesser than the proportion of US adults in 2009. Save the StatCrunch image showing p-value and upload in next question.
Unusuаl event - If the prоbаbility оf it hаppening is less than 0.025. That is there is less than 2.5% chance that the event will happen. Abоut 52% of this college's student population are younger than 25 years. Suppose you surveyed a random sample of 420 students to find how many are younger than 25 years. Let X represent sample proportion of students younger than 25 years. Central limit theorem describes the distribution of sample proportion. The mean of the sampling distribution is [a] and standard deviation is [b]. Round to 2 decimals. Use these numbers for next question. Use Central Limit Theorem to find probability. In your sample of 420 students, what is the probability that the sample proportion of students younger than 25 years is less than 45%? [c] Do not round. Type or copy/paste as in StatCrunch output. In the college where 52% of students are younger than 25 years, we can claim that observing 50% (or lower) of students younger than 25 years in the sample is [d] (likely / unlikely / very unlikely).